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just pure fixed‑size subnetting

Exercise 1 // Class C, simple fixed subnetting

You are given the network: 192.168.50.0 /24
You must create 4 equal‑size subnets.

Tasks:

• Determine the new subnet mask
• Determine the block size
• List all subnet IDs

For the 3rd subnet, give:
Network address // Broadcast address
First usable // Last usable

Exercise 2 // Class B, moderate fixed subnetting

You are given the network: 172.16.0.0 /16
You must create 32 equal‑size subnets.

Tasks:

• Determine the new prefix length
• Determine the block size
• List the first 5 subnet IDs

For the last subnet, give:
Network address / Broadcast address
First usable / Last usable

Exercise 3 // Class A, larger space, more subnets

You are given the network: 10.0.0.0 /8
You must create 512 equal‑size subnets.

Tasks:

• Determine the new subnet mask
• Determine the increment in the octet where subnetting occurs
• Provide the subnet ID of subnet #257

For subnet #257, give:
Network address / Broadcast address
First usable / Last usable

Exercise 4 // Class C, many host per subnet

You are given the network: 198.51.100.0 /24
You must create subnets that each support at least 50 hosts.
(Still fixed‑size, no VLSM — all subnets identical.)

Tasks:

• Determine the required subnet mask
• Determine the number of subnets created
• List the first 4 subnet IDs

For the 2nd subnet, give:
Network address / Broadcast address
First usable addr / Last usable addr

Exercise 5 // Class B, high‑difficulty fixed subnetting

You are given the network: 172.20.0.0 /16
You must create subnets that each support at least 900 hosts.
All subnets must be equal size.

Tasks:

• Determine the new prefix length
• Determine the number of subnets created
• Determine the block size
• Provide the subnet ID of subnet #14

For subnet #14, give:
Network address / Broadcast address
First usable addr / Last usable addr

oplossingen:

EXERCISE 1 — 192.168.50.0/24 into 4 equal subnets
New prefix & mask: /24 → /26 (255.255.255.192)
Block size: 256−192=64 → /26 blocks of 64 addresses

Subnets:

• 192.168.50. 0 /26
• 192.168.50. 64 /26
• 192.168.50.128 /26
• 192.168.50.192 /26

3rd subnet (192.168.50.128 /26):
Network: 192.168.50.128
First usable: 192.168.50.129
Last usable: 192.168.50.190
Broadcast: 192.168.50.191

EXERCISE 2 – 172.16.0.0/16 into 32 subnets
New prefix: /21
Mask: 255.255.248.0
Block size: 8 (third octet)
First 5 subnets:
172.16.0.0
172.16.8.0
172.16.16.0
172.16.24.0
172.16.32.0
Last subnet:
Network: 172.16.248.0
First usable: 172.16.248.1
Last usable: 172.16.255.254
Broadcast: 172.16.255.255

EXERCISE 3 – 10.0.0.0/8 into 512 subnets
New prefix: /17
Mask: 255.255.128.0
Increment: 128 in 3rd octet
Subnet #257:
Network: 10.128.0.0
First usable: 10.128.0.1
Last usable: 10.128.127.254
Broadcast: 10.128.127.255

EXERCISE 4 – 198.51.100.0/24, ≥50 hosts
New prefix: /26
Mask: 255.255.255.192
Number of subnets: 4
First 4 subnets:
198.51.100.0
198.51.100.64
198.51.100.128
198.51.100.192
2nd subnet details:
Network: 198.51.100.64
First usable: 198.51.100.65
Last usable: 198.51.100.126
Broadcast: 198.51.100.127

EXERCISE 5 – 172.20.0.0/16, ≥900 hosts
New prefix: /22
Mask: 255.255.252.0
Number of subnets: 64
Block size: 4 (third octet)
Subnet #14:
Network: 172.20.52.0
First usable: 172.20.52.1
Last usable: 172.20.55.254
Broadcast: 172.20.55.255